Question

The ground state electronic configuration of $S$ is $3s^{2}3p^4$ How does it from the compound $S{F}_6$?

• A. Due to octahedral shape of $S$ atoms
• B. Due to the presence of vacant 3d-orbitals which provide 6 unpaired electrons in excited state
• C. Due to $s{p}^3$ hybridization of $S$ atom which provides 6 electrons to 6 F atoms
• D. Due to presence of $3\sigma$ and $3\pi$ bonds between $S$ and $F$

Answer 1

Answer: (B)

Due to the presence of vacant 3d-orbitals which provide 6 unpaired electrons in excited state

$Sulpher$ has $3d$ orbital that allow it to expand the valency up to $6$ and $F$ pair with these orbitals.

So the correct option is [B].