Question

The ground state energy of hydrogen atom is -13.6 eV. The energy of second excited state of $H{e}^{+}$ ion in eV is

• A. -6.04
• B. -27.2
• C. -54.4
• D. -3.4

Answer 1

The correct option is A -6.04

For hydrogen like species, energy of $n^{th}$ shell is given by
$(E{)}_{n^{th}}=(E_{GND}{)}_{H}X\frac{Z^2}{n^2}$
where,
$(E{)}_{n^{th}}$ is the energy of $n^{th}$ state of hydrogen like species
$(E_{GND}{)}_H$ is the ground state energy of hydrogen atom
Z is the atomic number
Thus,
$E_{3^{rd}}\left(H{e}^{+}\right)=(-13.6eV)X\frac{2^2}{3^2}=-6.04eV$
Hence, correct option is (a).