The group having isoelectronic species is

O^{2 -}, F^{-}, N a^{+}, M g^{2 +}

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O^{-}, F^{-}, N a, M g^{2 +}

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O^{2 -}, F^{-}, N a, M g^{2 +}

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O^{-}, F^{-}, N a^{+}, M g^{2 +}

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Solution

The correct option is A $O^{2 -}, F^{-}, N a^{+}, M g^{2 +}$
$O$ gains 2 electrons so $O^{2 -}$ has 10 electrons.

$F$ gains 1 electron, $F^{-}$ has 10 electrons.

$N a$ loses 1 electron, $N a^{+}$ has 10 electrons.

$M g$ loses 2 electrons so $M g^{2 +}$ has 10 electrons.

So, option A is correct.

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