Question

The group having isoelectronic species is :

• A. $O^{-},F^{-},Na,M{g}^{+}$
• B. $O^{2-},F^{-},Na,M{g}^{2+}$
• C. $O^{-},F^{-},N{a}^{+},M{g}^{2+}$
• D. $O^{2-},F^{-},N{a}^{+},M{g}^{2+}$

Answer 1

The correct option is D $O^{2-},F^{-},N{a}^{+},M{g}^{2+}$

Isoelectronic elements are those which have the same number of electrons.

$O^{-}$ has 9 electrons, $O^{2-}$ has 10 electrons.

$F^{-}$ has 10 electrons.

$Na$ has 11 electrons. $N{a}^{+}$ has 10 electrons.

$M{g}^{+}$ has 11 electrons, $M{g}^{2+}$ has 10 electrons.

Correct option is D.