The group reagent for third group is $N H_{4} O H$ in presence of:

(N H_{4})_{2} C O_{3}

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N a C l

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(N H_{4})_{2} S O_{4}

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N H_{4} C l

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Solution

The correct option is D $N H_{4} C l$
Group $3^{r d}$ ions are precipitated as hydroxides and the addition of ${N H}_{4} C l$ suppresses the ionisation of ${N H}_{4} O H$ so that only group $3^{r d}$ cations are precipitated as hydroxides because of their low solubility products.

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