The H-C-F- of 4 - 27 - 3125-8 - 9 - 25 - 7 and 16 - 81 - 5 - 11 - 49 is

The correct option is D 5404 × 27 × 3125, 8× 9 × 25 × 7, 16 × 81 × 5 × 11 × 49 =2 × 2 × 3 × 3 × 3 × 5 × 5 × 5 × 5 × 5 × 5, 8 × 9 × 25 × 7, 16 × 81 × 5 × 11 × ...

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Quantitative Aptitude

Highest Power of a Number

The H.C.F. of...

Question

The H.C.F. of $4 \times 27 \times 3125, 8 \times 9 \times 25 \times 7$ and $16 \times 81 \times 5 \times 11 \times 49$ is _____.

180

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360

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540

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1260

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Solution

The correct option is C 540
$4 \times 27 \times 3125, 8 \times 9 \times 25 \times 7, 16 \times 81 \times 5 \times 11 \times 49 = 2 \times 2 \times 3 \times 3 \times 3 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5, 8 \times 9 \times 25 \times 7, 16 \times 81 \times 5 \times 11 \times 49 = 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 3 \times 5 \times 7 \times 7 \times 11 ∴ H . C . F . = 2 \times 2 \times 3 \times 3 \times 3 \times 5 = 540$

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Similar questions

The H.C.F. of 4 $\times$ 27 $\times$ 3125, 8 $\times$ 9 $\times$ 25 $\times$ 7 & 16 $\times$ 81 $\times$ 5 $\times$ 11 $\times$ 49 is ____.

Q. What is the H.C.F. of

4 \times 27 \times 3125, 8 \times 9 \times 25 \times 7, 16 \times 81 \times 5 \times 11 \times 49 ?

Evaluate:

{(\frac{81}{16})}^{- \frac{3}{4}} \times ⎡ ⎣ {(\frac{25}{9})}^{- \frac{3}{2}} \div {(\frac{5}{9})}^{- 3} ⎤ ⎦

Q. The value of

\frac{l o g_{3} 5 \times l o g_{25} 27 \times l o g_{49} 7}{l o g_{81} 3}

Q. Prove that :

4 log \frac{24}{25} - 16 log \frac{9}{10} + 7 log \frac{81}{80} = log 5

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The H.C.F. of 4×27×3125,8×9×25×7 and 16×81×5×11×49 is _____.

The correct option is C 5404×27×3125,8×9×25×7,16×81×5×11×49=2×2×3×3×3×5×5×5×5×5×5,8×9×25×7,16×81×5×11×49=2×2×2×2×3×3×3×3×5×7×7×11∴H.C.F.=2×2×3×3×3×5=540

The H.C.F. of $4 \times 27 \times 3125, 8 \times 9 \times 25 \times 7$ and $16 \times 81 \times 5 \times 11 \times 49$ is _____.