The H.C.F. of 420 and 130 is .

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Solution

The correct option is C 10
Step 1: Applying Euclid's division lemma to 420 and 130, we get
$420 = 130 \times 3 + 30.$

Step 2: Since 30 is not equal to 0, we apply the lemma again, but to 130 and 30 to get
$130 = 30 \times 4 + 10.$

Step 3: Since 10 is not equal to 0, we apply the division lemma to 30 and 10 to get
$30 = 10 \times 3 + 0.$

Since the remainder is zero, the divisor 10 is the HCF of 420 and 130.

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