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Question

The H.C.F. of 420 and 130 is .

A
11
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B
10
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C
13
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Solution

The correct option is B 10
Step 1: Applying Euclid's division lemma to 420 and 130, we get
420=130×3+30.

Step 2: Since 30 is not equal to 0, we apply the lemma again, but to 130 and 30 to get
130=30×4+10.

Step 3: Since 10 is not equal to 0, we apply the division lemma to 30 and 10 to get
30=10×3+0.

Since the remainder is zero, the divisor 10 is the HCF of 420 and 130.

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