The H.C.F of 45 and 81 is .
Using prime factorisation method:
345315551 ∴45=3×3×5
38132739331 ∴81=3×3×3×3
45=5×3×3 81=3×3×3×3 ∴ The HCF is 3×3=9
Find HCF of 81 and 237 and express it as a linear combination of 81 and 237 i.e., HCF (81,237)= 81x + 237y for some x and y. Please explain.