The correct option is C 13
Step 1: Since 117>65, we apply Euclid's division lemma to 117 to get
117=65×1+52.
Step 2: Since 52≠0, we apply the division lemma to 65 and 52 to get
65=52×1+13.
Step 3: Since 13≠0, we apply the division lemma to 52 and 13 to get
52=13×4+0.
Since the divisor at this step is 13 and remainder is zero, the HCF of 117 and 65 is 13.