The H-C-F- of the fractions 8-21- 12-35 and 32-7 is

The correct option is A 4/105 8= 2 ^ 3 12= 2 ^ 2 × 3 32= 2 ^ 5 HCF(8,12,32)= 2 ^ 2 =4 21=3× 7 35=5× 7 7=1× 7 LCM ...

261

You visited us 261 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Addition of Rational Numbers

The H.C.F. of...

Question

The H.C.F. of the fractions $\frac{8}{21}$ , $\frac{12}{35}$ and $\frac{32}{7}$ is

\frac{4}{105}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{192}{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{4}{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{5}{109}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{4}{105}$
$8 = 2^{3} 12 = 2^{2} \times 3 32 = 2^{5} H C F (8, 12, 32) = 2^{2} = 4 21 = 3 \times 7 35 = 5 \times 7 7 = 1 \times 7 L C M (21, 35, 7) = 3 \times 5 \times 7 = 105$
HCF of a fraction $=$ HCF of numerator / LCM of denominator

HCF of fraction $=$ $\frac{4}{105}$

Suggest Corrections

Similar questions

Verify each of the following :

(i) $(\frac{5}{7} \times \frac{12}{13}) \times \frac{7}{18} = \frac{5}{7} \times (\frac{12}{13} \times \frac{7}{18})$
(ii) $\frac{- 13}{24} \times (\frac{- 12}{5} \times \frac{35}{36}) = (\frac{- 13}{24} \times \frac{- 12}{5}) \times \frac{35}{36}$
(iii) $(\frac{- 9}{5} \times \frac{- 10}{3}) \times \frac{21}{- 4} = \frac{- 9}{5} \times (\frac{- 10}{3} \times \frac{21}{- 4})$

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

Slide the slider to the value of : (4 \times 8) \times 5 + (35 + 12) - 7

Fill in the blanks.

(i) $(\frac{- 3}{17}) + (\frac{- 12}{5}) = (\frac{- 12}{5}) + (. . . . .)$

(ii) $- 9 + \frac{- 21}{8} = (. . . . . .) + (- 9)$

(iii) $(\frac{- 8}{13} + \frac{3}{7}) + (\frac{- 13}{4}) = (. . . . . .) + [\frac{3}{7} + (\frac{- 13}{4})]$

(iv) $- 12 + (\frac{7}{12} + \frac{- 9}{11}) = (- 12 + \frac{7}{12}) + (. . . . .)$

(v) $\frac{19}{- 5} + (\frac{- 3}{11} + \frac{- 7}{8}) = {\frac{19}{- 5} + (. . . . .)} + \frac{- 7}{8}$

(vi) $\frac{- 16}{7} + . . . . . = . . . . . . + \frac{- 16}{7} = \frac{- 16}{7}$

Find:

(i) (ii) (iii)

(iv) (v) (vi)

Join BYJU'S Learning Program

The H.C.F. of the fractions 821, 1235 and 327 is

The correct option is A 41058=2312=22×332=25HCF(8,12,32)=22=421=3×735=5×77=1×7LCM(21,35,7)=3×5×7=105HCF of a fraction = HCF of numerator / LCM of denominatorHCF of fraction = 4105

The H.C.F. of the fractions $\frac{8}{21}$ , $\frac{12}{35}$ and $\frac{32}{7}$ is