Question

The H.C.F. of two numbers is $29$ and their L.C.M. is $1160$. If one of the numbers is $145$, find the number.

Answer 1

Let the 2nd number be $M$.

Now, we know that,

$$\begin{gathered} HCF\times LCM=Productoftwonumbers \\ 29\times 1160=145\times M \\ M=\frac{29\times 1160}{145} \\ M=232 \end{gathered}$$

Hence, the 2nd number is $232$.