The H.C.F. of $x^{2} + 2 x - 8, x^{3} - 4 x^{2} + 4 x$ and $x^{2} - 4$ is .

x - 2

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x + 3

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x^{2}

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x + 1

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Solution

The correct option is A $x - 2$
Factors of :
$x^{2} + 2 x - 8 \to (x + 4) (x - 2)$

$x^{3} - 4 x^{2} + 4 x \to x (x - 2)^{2}$

$x^{2} - 4 \to (x + 2) (x - 2)$

The highest common factor for the above expressions is $(x - 2)$
$∴$ H.C.F = $(x - 2)$

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