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Polar Covalent Compounds

The H-F bon...

Question

The $H - F$ bond and the $H - I$ bond have different values for their bond polarity. Which of the following statements correctly identifies the bond that is more polar and gives the correct reason for this difference?

The

H - F

bond is more polar than the

H - I

bond because iodine is more electronegative than fluorine

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The

H - F

bond is more polar than the

H - I

bond because fluorine is more electronegative than iodine

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The

H - I

bond is more polar than the

H - F

bond because iodine is more electronegative than fluorine

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The

H - I

bond is more polar than the

H - F

bond because fluorine is more electronegative than iodine

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Solution

The correct option is B The $H - F$ bond is more polar than the $H - I$ bond because fluorine is more electronegative than iodine
In $H - F$ bond, the fluorine atom is more electronegative than $H$ atom. So, is the case for $H - I$ bond, I being more electronegative than hydrogen. Iodine being the larger radical, hydrogen can easily attract the valance electrons. So, $H - F$ bond is more polar than $H - I$ bond because fluorine electronegative.

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