Question

The $H-F$ bond and the $H-I$ bond have different values of their bond polarity. Which of the following statements correctly identifies the bond that is more polar and gives the correct reason for this difference?

• A. The $H-I$ bond is more polar than the $H-F$ bond because iodine is more electronegative than fluorine.
• B. The $H-F$ bond is more polar than the $H-I$ bond because fluorine is more electronegative than iodine.
• C. Depends on the temperature.
• D. None of these.

Answer 1

Answer: (B)

The $H-F$ bond is more polar than the $H-I$ bond because fluorine is more electronegative than iodine.

$H-F$ is more polar then $H-I$ due to the high electronegativity of $F$, it attracts the shared pair of $e^{-}$ towards itself more, thereby acquiring $S-$ charge on $F$ and $S^{+}$ on $H$.

$H^{\delta +}-F^{\delta -}$