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Dipole Moment

The H-OH bond...

Question

The H-OH bond angle in water is 105. The dipole distance being $0.94 A^{0}$ . The dipole moment for molecule is 1.85 debye. Calculate the charge on oxygen atom.
[ $cos 105^{0}$ = 0.259(approx)].

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Solution

Dipole moment $=$ distance $\times$ charge.
$1.85 = 0.94 \times$ charge
charge $= \frac{1.85}{0.94} = 1.96$
charge on oxygen atom $= 2$ .

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