The haemoglobin from red corpuscles of most mammals contains approximately 0.33% of iron by weight. The molecular weight of haemoglobin is 67,200. The number of iron atoms in each molecule of haemoglobin is:

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Solution

The correct option is B 4
$100 g$ sample of hemoglobin contains 0.33 g iron
67200g sample of hemoglobin contains $= 0.33 \times 67200 / 100 = 221.8 g$
$∴$ number of iron atoms per molecule of hemoglobin $= 221.8 / 56 = 4$

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Q. The haemoglobin from the red blood corpuscles of most mammals contains approximately 0.33 % of iron by weight. The molecular weight of haemoglobin is 67,200. The number of iron atoms in each molecule of haemoglobin is:

(Atomic weight of iron = 56)

Q. The haemoglobin from red corpuscles of most mammels contain approximately 0.33% of iron by mass. The molecular mass of haemoglobin is 67200. The number of iron atoms in each molecule of haemoglobin is:

Q. The haemoglobin of most mammals contains approximately

0.33 %

of iron by mass. The molecular mass of haemoglobin is

67200

. The number of iron atoms in each molecule of haemoglobin is:

Haemoglobin contains 0.33% of iron by weight . The molecular weight of haemoglobin is approximately 67200 . The number of iron atoms ( at . wt. of Fe=56) present in one molecule of haemoglobin is

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The haemoglobin from red corpuscles of most mammals contains approximately 0.33% of iron by weight. The molecular weight of haemoglobin is 67,200. The number of iron atoms in each molecule of haemoglobin is:

The correct option is B 4100g sample of hemoglobin contains 0.33 g iron67200g sample of hemoglobin contains =0.33×67200/100=221.8g∴ number of iron atoms per molecule of hemoglobin =221.8/56=4

The correct option is B 4
$100 g$ sample of hemoglobin contains 0.33 g iron
67200g sample of hemoglobin contains $= 0.33 \times 67200 / 100 = 221.8 g$
$∴$ number of iron atoms per molecule of hemoglobin $= 221.8 / 56 = 4$