The haemoglobin of most mammals contains approximately 0.33% of iron by mass. The molecular mass of haemoglobin is 67200. The number of iron atoms in each molecule of haemoglobin is:
A
3
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B
4
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C
2
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D
6
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Solution
The correct option is B4 Percentage of Fe=0.33
Molecular weight of haemoglobin = 67200
Weight of Fe present=(0.33100)×67200=221.8
One Fe weights 55.8g
Therefore, number of Fe atoms = 221.855.8=4
Hence, 4 atoms of iron are present in one molecule of haemoglobin.