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Standard VII

Chemistry

Half Life

The half-life...

Question

The half-life for the reaction, $N_{2} O_{5} \Rightarrow 2 N O_{2} + \frac{1}{2} O_{2}$ is 12 minutes at $30^{\circ} C$ . Starting with 100 g of $N_{2} O_{5}$ how many gram of $N_{2} O_{5}$ will remain after a period of 1 hour 36 minutes.

1.25 g

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0.39 g

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1.77 g

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0.5 g

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Solution

The correct option is B 0.39 g
One hour 36 minutes, i.e., 96 minutes is 8 half lives

Hence the amount left over is $\frac{100}{2^{8}} = \frac{100}{256} = 0.39 g$

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Similar questions

Q. The half-life for the reaction,

N_{2} O_{5} \Rightarrow 2 N O_{2} + \frac{1}{2} O_{2}

is 12 minutes at

30^{\circ} C

. Starting with 100 g of

N_{2} O_{5}

how many gram of

N_{2} O_{5}

will remain after a period of 1 hour 36 minutes.

Q. The half life for the first order reaction

N_{2} O_{5} \to 2 N O_{2} + \frac{1}{2} O_{2}

24

hrs. at

30^{\circ} C

. Starting with

10 g

N_{2} O_{5}

how many grams of

N_{2} O_{5}

will remain after a period of

96

hours?

Q. The half life for the first order reaction,

N_{2} O_{5} \to 2 N O_{2} + 1 / 2 O_{2}

24

hours at

30^{o}

C. Starting with

10

g of

N_{2} O_{5}

, how many grams of

N_{2} O_{5}

will remain after a period of

96

hours?

Q. The half-life for the reaction

N_{2} O_{5} \to 2 N O_{2} + \frac{1}{2} O_{2}

2.4 h

STP
Starting with

10.8 g

N_{2} O_{5}

how much oxygen will be obtained after a peroid of

9.6 h

Q. The half life for the reaction,

N_{2} O_{5} ⇌ 2 {N O}_{2} + \frac{1}{2} O_{2}

in 24 hour at

30^{0} C

starting with 10g of

N_{2} O_{5}

how many grams of

N_{2} O_{5}

will remain after a period of 96 hours.

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The half-life for the reaction, N2O5⇒2NO2+12O2 is 12 minutes at 30∘C. Starting with 100 g of N2O5 how many gram of N2O5 will remain after a period of 1 hour 36 minutes.

The correct option is B 0.39 gOne hour 36 minutes, i.e., 96 minutes is 8 half lives Hence the amount left over is 10028=100256=0.39g

The half-life for the reaction, $N_{2} O_{5} \Rightarrow 2 N O_{2} + \frac{1}{2} O_{2}$ is 12 minutes at $30^{\circ} C$ . Starting with 100 g of $N_{2} O_{5}$ how many gram of $N_{2} O_{5}$ will remain after a period of 1 hour 36 minutes.

The correct option is B 0.39 g
One hour 36 minutes, i.e., 96 minutes is 8 half lives

Hence the amount left over is $\frac{100}{2^{8}} = \frac{100}{256} = 0.39 g$