Question

The half-life for the viral inactivation if in the beginning $1.5\%$ of the virus is inactivated per minute is :(Given: The reaction is of the first order)

• A. 76 min
• B. 66 min
• C. 56 min
• D. 46 min

Answer 1

The correct option is D 46 min

For the first order reaction for small finite change
$k_1=\frac{1}{\left[A\right]}\frac{\Delta \left[\Delta \right]}{\Delta t}\Rightarrow \frac{\Delta \left[A\right]/\left[A\right]}{\Delta t}=1.5\%mi{n}^{-1}$
= 0.015 $mi{n}^{-1}$
$t_{1/2}=\frac{0.693}{0.015mi{n}^{-1}}$ = 46.2 min $\approx$ $46min$