wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The half life of a first order reaction is 100 seconds at 280 K. If the temperature coefficient is 3.0 its rate constant at 290 K in s1 is:

A
2.08×103
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2.08×102
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6.93×103
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6.93×102
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 2.08×102
It has been observed that in homogeneous thermal reactions, for every ten degree rise in temperature, the rate constant is doubled or tripled. The ratio of rate constants at two temperatures separated by 10°C is called the temperature coefficient.
so k2k1=3 ( here )

Rate constant =0.693100=0.00693

logk2k1=log 3

log[k2](0.00693)=log 3

log k2log 0.00693=log 3

log k2=log 3+log 0.00693

log k2=0.4771+(2.16)

log k2=1.68

log k2=0.0208

k2=2.08×102

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Reactions in Solutions
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon