The half life of a radioactive element is $140$ days. After $560$ days, $1 g m$ of the element will be reduced to:

1 / 2 g m

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1 / 4 g m

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1 / 8 g m

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1 / 16 g m

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Solution

The correct option is C $1 / 16 g m$
$t_{1 / 2} = 140 d a y s$
After $4 t_{1 / 2}, 1 g m$ of element reduces to $(\frac{1}{2})^{4} \times 1 = \frac{1}{16} g m$

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