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Question

The half life of a radioactive sample is T. If the activities of the sample at time t1 and t2 (t1<t2) are R1 and R2 respectively, the number of atoms disintegrated in time t2t1 is proportional to,

A
(R1R2)T
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B
(R1+R2)T
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C
R1R2R1+R2T
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D
R1+R2T
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Solution

The correct option is A (R1R2)T

Activity or rate of decay is given by,

R=λN

R1=λN1 and R2=λN2

R1R2=λ(N1N2)=0.693T(N1N2)

N1N2=T0.693(R1R2)

(N1N2)(R1R2)T

Here, (N1N2) is the number of atoms disintegrated in the time interval (t1t2)

Hence, (A) is the correct answer.

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