You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Area of Polygon Using Coordinates

The half life...

Question

The half life of a ratio active source is T. If radio activities of the samples are $R_{1} - R_{2}$ at time

$T_{1} a n d T_{2}$ Respectively, then the number of atoms disintegrated in time $(T_{2} - T_{1})$ is proportional to

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B

$R_{1} = N_{1} λ R_{2} = N_{2} λ \frac{R_{1} - R_{2}}{λ} α N_{1} - N_{2}$

Suggest Corrections

Similar questions

Q. The radioactivity of a sample is

R_{1}

at time

T_{1}

and

R_{2}

at time

T_{2}

. If the half life of the specimen is

T

, number of atoms that have disintegrated in time

(T_{2} - T_{1})

is proportional to

Q. The half life of a radioactive sample is

T .

If the activities of the sample at time

t_{1}

and

t_{2}

(t_{1} < t_{2})

are

R_{1}

and

R_{2}

respectively, then the number of atoms disintegrated in time

t_{2} - t_{1}

is proportional to-

The radioactivity of a sample is R₁ at a time T₁ and R₂ at a time T₂. If the half-life of the specimen is T, the number of atoms that have disintegrated in the time (T₂-T₁) is proportional to:

Q. The radioactivity of a sample is

R_{1}

at time

T_{1}

and

R_{2}

at time

T_{2}

. If the half life of specimen is

T

, the number of atoms that have disintegrated in time

(T_{2} - T_{1})

is proportional to:

Q. The radioactivity of a sample is

R_{1}

at a time

T_{1}

and

R_{2}

at a time

T_{2}

. If the half-life of the specimen is

T

, the number of atoms that have disintegrated in the time

(T_{2} - T_{1})

is proportional to:

Join BYJU'S Learning Program

The half life of a ratio active source is T. If radio activities of the samples are R1−R2 at time T1 and T2 Respectively, then the number of atoms disintegrated in time (T2−T1) is proportional to

The correct option is B R1=N1λR2=N2λR1−R2λαN1−N2

The half life of a ratio active source is T. If radio activities of the samples are $R_{1} - R_{2}$ at time

$T_{1} a n d T_{2}$ Respectively, then the number of atoms disintegrated in time $(T_{2} - T_{1})$ is proportional to

The correct option is B

$R_{1} = N_{1} λ R_{2} = N_{2} λ \frac{R_{1} - R_{2}}{λ} α N_{1} - N_{2}$