Question

The half-life of a reaction becomes half when initial concentrations of reactants are made double. The order of the reaction will be:

• A. $1$
• B. $2$
• C. $0$
• D. $3$

Answer 1

Answer: (B)

$2$

$t_{1/2}\propto \frac{1}{a^{n-1}}$
$t_{1/2}\propto \frac{1}{a}$
where, $n=$ order of reaction for second order reaction.