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Charles' Law

The half -lif...

Question

The half -life of is 100. The time taken for the radioactivity of a sample of to decay to $(\frac{1}{16 t h})$ of its initial value is

A

400

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B

6.3

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C

40

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D

300

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Solution

The correct option is A
400

In one half-life, the sample decays to $\frac{1}{2}$ of its initial value.

So after 4 half-lives the sample decays to $\frac{1}{16 t h}$ of its initial value.

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