The half life of radioactive radon is $3.8$ days. In how much time $1 / 20$ fraction of radon will remain undecayed ?

16.5

days

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76

days

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3.8

days

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33

days

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Solution

The correct option is B $16.5$ days
Number of half lives required in which $1 / 20$ fraction of randon remains undecayed is ${log}_{2} 20 = 4.32$
So, Number of days is $3.8 \times 4.32 = 16.42 d a y s$

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The half life of radioactive radon is 3.8 days. In how much time 1/20 fraction of radon will remain undecayed ?

The correct option is B 16.5 daysNumber of half lives required in which 1/20 fraction of randon remains undecayed is log220=4.32So, Number of days is 3.8×4.32=16.42 days

The half life of radioactive radon is $3.8$ days. In how much time $1 / 20$ fraction of radon will remain undecayed ?

The correct option is B $16.5$ days
Number of half lives required in which $1 / 20$ fraction of randon remains undecayed is ${log}_{2} 20 = 4.32$
So, Number of days is $3.8 \times 4.32 = 16.42 d a y s$