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Question

The half-life of Te99 is 6 h. The activity of Te99 in a patient, 60 h after receiving an injection containing this radioisotope is at least 0.125 μCi. What was the minimum activity (in μCi) of the sample injected?

A
1.25
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B
12.5
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C
128
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D
125
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Solution

The correct option is C 128
Half life of sample, T=6 h
Age of sample t=60 h=10T
Number of half lives n=10
Activity A=A02nA0=A.2n=0.125×210=128 μCi

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