The half-life of Te99 is 6h. The activity of Te99 in a patient, 60h after receiving an injection containing this radioisotope is at least 0.125μCi. What was the minimum activity (in μCi) of the sample injected?
A
1.25
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B
12.5
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C
128
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D
125
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Solution
The correct option is C128 Half life of sample, T=6h Age of sample t=60h=10T Number of half lives n=10 Activity A=A02n⇒A0=A.2n=0.125×210=128μCi