The half life period of a radioactive element is $50$ days. The activity of the substance gets reduced to $1 / 8$ of the original value in:

50 d a y s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100 d a y s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25 d a y s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

150 d a y s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $150 d a y s$
$t_{1 / 2} = 50 d a y s$
Activity reduced to $(\frac{1}{2})^{3}$

i.e. $n = 3$
Lapsed time $= 50 \times 3 = 150 d a y s$

Suggest Corrections

Similar questions

The activity of a radioactive element reduces to $\frac{1}{16}$ of its original value in 36 years. The half life of the element is

(1 / 16) t h

30

\frac{1}{4}

\frac{1}{8}

\frac{1}{16^{t h}}

20

\frac{7}{8} t h

Join BYJU'S Learning Program