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Question

The half-life period of radon is 3.8 days. After how many days will only one-twentieth of radon sample be left over?

A
12.65 days
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B
24.75 days
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C
42.35 days
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D
6.5 days
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Solution

The correct option is A 12.65 days
We know that K=0693t12=0.6933.8=0.182 day1
Let the initial amount of radon be N_0 and the amount left after t days be N which is equal to N010
Applying the equation,
t=2.303KlogN0Nt=2.3030.182logN0N010=2.3030.182log 10=12.65 days

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