The half year period for a zero order reaction is equal to:

2 K / [A] o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{[A]_{o}}{2 k}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{0.693}{k}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{0.693}{k [A]_{o}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{[A]_{o}}{2 k}$
Half Year Period for a Zero order reaction is $\frac{[A_{0}]}{2 k}$
Where $[A_{0}] =$ initial concentration
$k =$ rate constant

Suggest Corrections

Similar questions

Match the following
Order of reaction Half-life period
1)1st order reaction a) $(k a_{0})^{- 1}$
2) Second order reaction b) $\frac{0.693}{k}$
3) Zero order reaction c) $\frac{a_{0}}{2 k}$

Q. If the half life period of a reaction is

0.693 k

, its order will be

Q. Let k be a positive real number and let

A = ⎡ ⎢ ⎢ ⎣ \begin{matrix} 2 k - 1 & 2 \sqrt{k} & 2 \sqrt{k} 2 \sqrt{k} & 1 & - 2 k - 2 \sqrt{k} & 2 k & - 1 \end{matrix} ⎤ ⎥ ⎥ ⎦

B = ⎡ ⎢ ⎢ ⎣ \begin{matrix} 0 & 2 k - 1 & \sqrt{k} 1 - 2 k & 0 & 2 \sqrt{k} - \sqrt{k} & - 2 \sqrt{k} & 0 \end{matrix} ⎤ ⎥ ⎥ ⎦

If det

(A d j (A)) + d e t (A d j (B)) = 10^{o}

then

[k]

is equal to.

Q. Time required to complete half of the reactant in a zero order reaction is equal to a/(2k).

Join BYJU'S Learning Program

The half year period for a zero order reaction is equal to:

The correct option is B [A]o2kHalf Year Period for a Zero order reaction is [A0]2kWhere [A0]= initial concentrationk= rate constant

The correct option is B $\frac{[A]_{o}}{2 k}$
Half Year Period for a Zero order reaction is $\frac{[A_{0}]}{2 k}$
Where $[A_{0}] =$ initial concentration
$k =$ rate constant