MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Second Order Reaction

The halflife ...

Question

The halflife of a reaction was halved as the initial concentration of a reactant was double in which of the following order reactions :

A

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2$
for second order
$t_{^{1} /_{2}} = \frac{1}{K a}$
$i f a \to 2 a$
$t_{^{1} /_{2}} = \frac{1}{2} (\frac{1}{K a})$
So, second order.

Suggest Corrections

thumbs-up

0

Similar questions

Q. The half life for a given reaction was doubled as the initial concentration of the reactant was doubled. The order of the reaction is:

Q. The half-life of a reaction is halved as the initial concentration of the reactant is doubled. The order of the reaction is?

Q. The half life period (

t_{1 / 2}

) of a reaction is halved as the initial concentration of the reactant is doubled. What is the order of the reaction ?

t_{1 / 2}

of a reaction is doubled as the initial concentration of the reactant is doubled. What is the order of the reaction?

Q. The reaction A

+

\to

products is first order in each of the reactants. What is the change in the rate of reaction if the concentration of A is halved and concentration of B is doubled?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Integrated Rate Equations

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Second Order Reaction

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon