Question

The handle of a nutcracker is 16 cm long and a nut is placed 2 cm from its hinge. If a force of 4kgf is applied at the end of the handle to crack it, what weight if simply, placed on the nut will crack it

Answer 1

Step: 1

Given

Distance of Nut from Fulcrum = 2 cm

Distance of effort from Fulcrum = 16 cm

Effort = 4 kgf

Let the load place is y kgf

Step - 2

Diagram -

Step - 3

Formula used :

load (nut) x Distance of nut from fulcrum = Effort x Distance of effort from fulcrum

y x 2 = 4 x 16

y = 32 kgf

Hence, the required load is 32 kgf.