The handle of a water pump is $90 c m$ long from its piston rod. If the pivot handle is at a distance of $15 c m$ from the piston rod, calculate the mechanical advantage of the handle.

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Solution

Given:
Load arm = $15 c m$
length of water pump= $90 c m$
Effort arm = handle of water pump - load arm = $90 - 15 = 75 c m$

To calculate mechanical advantage:
Formula used :
$M A = \frac{E f f o r t a r m}{l o a d a r m} \Rightarrow M A = \frac{75}{15} = 5$

Answer:
The mechanical advantage of the handle is $5$ .

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The handle of a water pump is 90cm long from its piston rod. If the pivot handle is at a distance of 15cm from the piston rod, calculate the mechanical advantage of the handle.

Given:Load arm =15cmlength of water pump=90cmEffort arm = handle of water pump - load arm =90-15=75cm To calculate mechanical advantage:Formula used :MA=Effortarmloadarm⇒MA=7515=5 Answer:The mechanical advantage of the handle is 5.

The handle of a water pump is $90 c m$ long from its piston rod. If the pivot handle is at a distance of $15 c m$ from the piston rod, calculate the mechanical advantage of the handle.