The harmonic mode which resonates with a closed pipe of length 22cm, when excited by a 1875Hz source and the number of nodes present in it respectively are (velocity of sound in air =330ms−1):
A
1st,1
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B
3rd,1
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C
3rd,2
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D
5th,4
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E
5th,3
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Solution
The correct option is E5th,3 Velocity of sound=330ms−1 Length of closed pipe=22cm=22×10−2m Fundamental frequency of stationary wave, v0=v4l=3304×22×10−2 v0=330×1024×22=30008 v0=375Hz 3v0=375×3=1125 5v0=5×375=1875 Thus we get 5th harmonic and number of nodes =3 Note: In closed pipe, odd harmonics are produced.