The HCF and the LCM of two algebraic expression are (a -5) and 2a3+3a2−44a−105 respectively. If one of the expressions is 2a2−3a−35, the other will be
A
a2−2a−15
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B
a2−3a−10
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C
a2−4a+15
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D
2a2−5a+10
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Solution
The correct option is Ba2−2a−15 Since, H.C.F×L.C.M=one expression× second expression ∴ Required expression =H.C.F.×L.C.MKnown expression =(a−5)(2a3+3a2−44a−105)2a2−3a−35 =(a−5)(a+3)(2a2−3a−35)2a2−3a−35 =(a−5)(a+3) =a2−2a−15. Option A is correct.