The HCF, LCM, and one of the numbers is given. Find the other number in each of the following.
HCF $= 8$ ,LCM $= 224$ ,First number $= 56$

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Solution

HCF and LCM of two numbers:
It is given that
HCF $= 8$ ,LCM $= 224$ ,First number $= 56$
We know that $H C F \times L C M = P r o d u c t o f t h e t w o n u m b e r s$
$\Rightarrow$ $8 \times 224$ $=$ $56 \times$ Second number
$\Rightarrow$ Second number $= 32$
Hence, the second number $=$ $\frac{8 \times 224}{56}$ $= 32$

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The HCF, LCM, and one of the numbers is given. Find the other number in each of the following.HCF =8,LCM =224,First number =56

HCF and LCM of two numbers:It is given thatHCF =8,LCM =224,First number =56We know thatHCF×LCM=Productofthetwonumbers⇒ 8×224 =56×Second number⇒ Second number =32Hence, the second number= 8×22456 =32

The HCF, LCM, and one of the numbers is given. Find the other number in each of the following.
HCF $= 8$ ,LCM $= 224$ ,First number $= 56$