The HCF of 22- 32- 52- 24- 34- 53- 11-2 - 32- 52- 24- 34- 53- 11 is-

The correct option is C 4502^2×3^2×5^2, 2^4×3^4×5^3×11, 2×3^2×5^2, 2^4 × 3^4 × 5^3 × 11 In H.C.F. we take the highest common factor. So, highest common factor ...

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Byju's Answer

Standard VIII

Mathematics

Factorisation by Common Factors

The HCF of 22...

Question

The HCF of $2^{2} \times 3^{2} \times 5^{2}, 2^{4} \times 3^{4} \times 5^{3} \times 11, 2 \times 3^{2} \times 5^{2}, 2^{4} \times 3^{4} \times 5^{3} \times 11$ is:

350

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400

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450

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None of above

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Solution

The correct option is C 450
$2^{2} \times 3^{2} \times 5^{2}$
$2^{4} \times 3^{4} \times 5^{3} \times 11$
$2 \times 3^{2} \times 5^{2}$
$2^{4} \times 3^{4} \times 5^{3} \times 11$
HCF (of above numbers) $=$ Product of the smallest power of each common prime factor in the numbers
$= 2^{1} \times 3^{2} \times 5^{2}$
$= 2 \times 9 \times 25 = 450$

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Similar questions

Q. If a =

2^{3} \times 3^{3} \times 7^{2}

and

b = 2^{2} \times 3^{2} \times 5^{3},

which is true?

Q. Simplify:

\frac{{(5^{- 3})}^{2} \times {(3^{4})}}{{(3^{- 2})}^{- 3} \times {(5^{3})}^{- 2}}

Q. Simplify

\frac{(5^{- 3})^{2} \times 3^{4}}{(3^{- 2})^{- 3} \times (5^{3})^{- 2}}

Q. If

32 \times 41 = 15; 51 \times 34 = 46; 41 \times 52 = 37

, then

87 \times 53 = ?

HCF of $(2^{3} \times 3^{2} \times 5), (2^{2} \times 3^{3} \times 5^{2}) a n d (2^{4} \times 3 \times 5^{3} \times 7)$ is

(a) 30 (b) 48 (c) 60 (d)105

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The HCF of 22×32×52,24×34×53×11,2×32×52,24×34×53×11 is:

The correct option is C 45022×32×5224×34×53×112×32×5224×34×53×11HCF (of above numbers) = Product of the smallest power of each common prime factor in the numbers=21×32×52=2×9×25=450

The HCF of $2^{2} \times 3^{2} \times 5^{2}, 2^{4} \times 3^{4} \times 5^{3} \times 11, 2 \times 3^{2} \times 5^{2}, 2^{4} \times 3^{4} \times 5^{3} \times 11$ is: