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Question

The HCF of 2 numbers is 11 and their LCM is 693 If their sum is 176 find the numbers

A
99, 77
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B
110, 66
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C
88, 77
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D
121, 44
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Solution

The correct option is A 99, 77
Let the number are a and b
Then ab=LCM×HCF
ab=693×11
ab=7623
a=7623b
According to the question
a+b=176
7623b+b=176
b2176b+7623=0
b277b99b+7623
b(b77)99(b77)
(b77)(b99)
b=77or99
Hence a = 77 or 99
Then the numbers are 77,99.

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