The HCF of 2 numbers is 11 and their LCM is 693 If their sum is 176 find the numbers
A
99, 77
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B
110, 66
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C
88, 77
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D
121, 44
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Solution
The correct option is A 99, 77 Let the number are a and b Then ab=LCM×HCF ab=693×11 ab=7623 a=7623b According to the question a+b=176 7623b+b=176 b2−176b+7623=0 b2−77b−99b+7623 b(b−77)−99(b−77) (b−77)(b−99) b=77or99 Hence a = 77 or 99 Then the numbers are 77,99.