The HCF of52,130 is
HCF by Prime factorization method.
The factors of52=2x2x13
The factors of 130=2x13x5
The common factors are 2,13.
Then HCF =2×13=26.
Therefore, HCF of52,130 is 26.
HCF of (23×32×5),(22×33×52) and (24×3×53×7) is
(a) 30 (b) 48 (c) 60 (d)105
HCF of 130 and 42 is 2. So how can we prove the reverse order ie,2 is the HCF of 130 and 42
Find the HCF of 52 and 117 and express it in form 52x + 117y.