The HCF of all possible pairs among four numbers is $3$ , and the LCM of the four numbers is $198 .$ What is the product of the numbers?

$2673$

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$32076$

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$16038$

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$5346$

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Solution

The correct option is D
$5346$

Given LCM $= 198$
Let the numbers be $3 a, 3 b, 3 c, 3 d .$
$3 a b c d = 198$
$a b c d = 198 / 3 = 66$
Product of all numbers $= 3^{4} \times 66 = 5346$
Hence option d is the answer.

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