Question

The HCF of $\frac{5}{9},\frac{13}{24}and\frac{11}{18}is$

Answer 1

H.C.F of $\frac{5}{9},\frac{13}{24},\frac{11}{18}$

$=\frac{H.C.F(5,13,11)}{L.C.M(9,24,18))}$

$5,3,11$ are prime numbers.Hence their H.C.F$=1$

Factors of $9=3\times 3$

Factors of $24=2\times 2\times 3\times 2$

Factors of $18=2\times 3\times 3$

L.C.M$(9,18,24)=3\times 3\times 2\times 2\times 2=72$

$\therefore H.C.F(\frac{5}{9},\frac{13}{24},\frac{11}{18})=\frac{1}{72}$