Question

The HCF of $\frac{9}{10},\frac{12}{25},\frac{18}{35}$ and $\frac{21}{40}$ is

• A. $\frac{3}{1400}$
• B. $\frac{252}{5}$
• C. $\frac{8}{1400}$
• D. $\frac{52}{140}$

Answer 1

The correct option is A $\frac{3}{1400}$

$\frac{9}{10},\frac{12}{25},\frac{18}{35}$ and $\frac{21}{40}$

$\Rightarrow \frac{630}{700},\frac{336}{700},\frac{360}{700}$ and $\frac{367.5}{700}$

$\Rightarrow \frac{1260}{1400},\frac{672}{1400},\frac{720}{1400}$ and $\frac{735}{1400}$

HCF of $1260,672,720$ and $735$

$=3$

$=\frac{3}{1400}$

Hence, the answer is $\frac{3}{1400}.$