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Question

The HCF of the polynomials 6(x236) and 36(x+6) is

A
6(x+6)
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B
6(x6)
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C
(x+6)
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D
(x6)
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Solution

The correct option is A 6(x+6)
First expression 6(x236)

6(x262) [a2b2=(a+b)(ab)]

6(x6)(x+6)

second expression 36(x+6)

6×6(x+6)

Therefore, in the two polynomials, 6(x+6) is the common factor.

so the required HCF=6(x+6)

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