The HCF of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, find the other.

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Solution

Let, the two numbers be a and b.

Let the value of a be 161.

Given: HCF = 23 and LCM = 1449

we know, a x b = HCF x LCM

⇒⇒ 161 x b = 23 x 1449

⇒⇒ Therefore, b = $fraction numerator 23 cross times 1449 over denominator 161 end fraction equals 33327 over 161 equals 207$

Hence, the other number b is 207

Suggest Corrections

223

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