Question

The HCF of two numbers is $28$ and their LCM is $336$. If one number is $112$, then the other number is _________.

• A. $64$
• B. $84$
• C. $34$
• D. $92$

Answer 1

Answer: (B)

$84$

We have, one number$=112$

Let other number be $x.$

$HCF=28,LCM=336$

Now, product of two numbers $=HCF\times LCM$

$\Rightarrow$ $112\times x$ $=28\times 336$

$\Rightarrow$ $x=\frac{28\times 336}{112}$

$\Rightarrow$ $x=84.$