The HCF of two polynomials $4 x^{2} (x^{2} - 3 x + 2) a n d 12 x (x - 2) (x^{2} - 4)$ is 4x(x - 2) The LCM of the two polynomials is

12 x (x^{2} - 4)

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12 x^{2} (x^{2} - 3 x + 4) (x^{2} - 2)

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12 x^{2} (x^{2} - 3 x + 2) (x^{2} - 4)

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12 x (x^{2} - 3 x - 2) (x^{2} - 4)

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Solution

The correct option is C $12 x^{2} (x^{2} - 3 x + 2) (x^{2} - 4)$
LCM = $\frac{p r o d u c t o f t h e p o l y n o m i a l s}{H C F}$
= $\frac{4 x^{2} (x^{2} - 3 x + 2) \times 12 x (x - 2) (x^{2} - 4)}{4 x (x - 2)}$
= $\frac{4 x^{2} (x - 2) (x - 1) \times 12 x (x - 2) (x - 2) (x + 2)}{4 x (x - 2)}$
= $12 x^{2} (x - 1) (x - 2) (x - 2) (x + 2)$
= $12 x^{2} (x^{2} - 3 x + 2) (x^{2} - 4)$

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Similar questions

\frac{2 x^{2} - 5 x + 3}{x^{2} - 3 x + 2} - \frac{2 x^{2} - 7 x - 4}{2 x^{2} - 3 x - 2}

- 2 x^{2} + 3 x - 4 = 0

\frac{1}{2} x^{2} - 3 x + 4

α, β

2 x^{2} + 3 x + 4 = 0

2 α, 2 β

a

b

p (x) = (x^{2} + 3 x + 2) (x^{2} + 2 x + a)

q (x) = (x^{2} + 7 x + 12) (x^{2} + 7 x + b)

(x + 3) (x + 4)

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