The head of the screw of a micrometer screw gauge advances linearly $5 m m$ in $10$ complete rotations. The pitch of the screw is:

1 m m

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0.5 m m

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2 m m

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0.2 m m

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Solution

The correct option is A $0.5 m m$
$P i t c h = \frac{L i n e a r d i s t a n c e c o v e r e d b y t h e c a p}{t o t a l n u m b e r o f r o t a t i o n s}$
$= \frac{5}{10} = 0.5 m m$

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The thimble of a screw gauge has 50 divisions. The spindle advances 1 mm when the screw is turned two revolutions.

(i) What is the pitch of screw gauge ?

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