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Measuring Length

The head scal...

Question

The head scale of a screw gauge has 200 divisions and its thimble moves by 0.5 mm along the main scale for one complete rotation of the screw. Find its least count.

A

0.00025

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B

0.005

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C

0.025

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D

0.0025

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Solution

The correct option is A 0.00025
Pitch $P = 0.5 m m$
Number of divisions $N = 200$
Least count of screw gauge $L . C . = \frac{P}{N} = \frac{0.5}{200} = 0.0025 m m = 0.00025 c m$

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