The heart of a man pumps $5 l i t r e s$ of blood through the arteries per minute at a pressure of $150 m m$ of mercury. If the density of mercury be $13.6 \times 10^{3} k g / m^{3}$ and $g = 10 m / s^{2}$ then the power of heart in watt is

1.50

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1.70

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2.35

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3.0

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Solution

The correct option is B $1.70$
Given,

$\frac{d V}{d t} = 5 L = \frac{5 \times 10^{- 3}}{60} m^{3} / s$

Power of heat,

$= P \cdot \frac{d V}{d t}$

$= ρ g h \times \frac{d V}{d t}$

$= (13.6 \times 10^{3}) (10) (0.15) \times \frac{5 \times 10^{- 3}}{60}$

$= 1.70 W$

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Similar questions

Q. The heart of a man pumps

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litres of blood through the arteries per minute at a pressure of

150 m m

of mercury. If the density of mercury be

13.6 \times 10^{3} k g / m^{3}

and

g = 10 m / s^{2}

then the power of heart in watt is:

The heart of a man pumps 5 litres of blood through the arteries per minute at a pressure of 150 $m m$ of mercury. If the density of mercury is $13.6 \times 10^{3} k g / m^{3}$ and $g = 10 m / s^{2}$ , then the power of heart in Watts is

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The heart of a man pumps 5 litres of blood through the arteries per minute at a pressure of 150 mm of mercury. If the density of mercury be 13.6×103 kg/m3 and g=10 m/s2 then the power of heart in watt is

The correct option is B 1.70Given,dVdt=5L=5×10−360m3/sPower of heat,=P⋅dVdt=ρgh×dVdt=(13.6×103)(10)(0.15)×5×10−360=1.70W

The heart of a man pumps $5 l i t r e s$ of blood through the arteries per minute at a pressure of $150 m m$ of mercury. If the density of mercury be $13.6 \times 10^{3} k g / m^{3}$ and $g = 10 m / s^{2}$ then the power of heart in watt is

The correct option is B $1.70$
Given,

$\frac{d V}{d t} = 5 L = \frac{5 \times 10^{- 3}}{60} m^{3} / s$

Power of heat,

$= P \cdot \frac{d V}{d t}$

$= ρ g h \times \frac{d V}{d t}$

$= (13.6 \times 10^{3}) (10) (0.15) \times \frac{5 \times 10^{- 3}}{60}$

$= 1.70 W$